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第8期2版:检测1.不变,相反。检测2.D。[^=2] 检测3.(1)2n-(2-n) (2)(2ab-πr^)-(ab-πr^)
=2n-2+n =2ab-πr^-ab+πr^
=(2n+n)-2 =(2ab-ab)+(-πr^+πr^)
=3n-2 =ab+0 =ab 问题1.(1)(4y-1)+3(y+5) =4y-1+3y+15 =(4y+3y)+(15-1)
=7y+14 [^^=3] (2)(-x^^-2y^)-(2x^^-2y^) =-x^^-2y^-2x^^+2y^ =(-x^^-2x^^)+(-2y^+2y^) =-3x^^+0 =3x^^
(3)(3a^-ab+7)-(-4a^+2ab+7) =3a^-ab+74a^-2ab-7
=(3a^+4a^)+(-ab-2ab)+(7-7) =7a^-3ab
问题2.(1)第一束:3x+2y+z (2)( =2x+2y+3z-3x-2y-z =(2x-3x)+(2y-2y)+(3z-z) 技能训练1.((D4.5x^-3x+1;27 6.(1)( =-xy+3y^-x^
(2)-3(2xy-2y^+8x^)+2(9x^+3xy-5y^) =-6xy+6y^-24x^+18x^+6xy-10y^
=(-6xy+6xy)+(6y^-10y^)+(-24x^+18x^) =-4y^-6x^
课程导报网 6
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课程导报网
2
课程导报网
课程导报网 3
课程导报网 4
5
课程导报网
第8期2版:检测1.不变,相反。检测2.D。[^=2] 检测3.(1)2n-(2-n) (2)(2ab-πr^)-(ab-πr^)
=2n-2+n =2ab-πr^-ab+πr^
=(2n+n)-2 =(2ab-ab)+(-πr^+πr^)
=3n-2 =ab+0 =ab 问题1.(1)(4y-1)+3(y+5) =4y-1+3y+15 =(4y+3y)+(15-1)
=7y+14 [^^=3] (2)(-x^^-2y^)-(2x^^-2y^) =-x^^-2y^-2x^^+2y^ =(-x^^-2x^^)+(-2y^+2y^) =-3x^^+0 =3x^^
(3)(3a^-ab+7)-(-4a^+2ab+7) =3a^-ab+74a^-2ab-7
=(3a^+4a^)+(-ab-2ab)+(7-7) =7a^-3ab
问题2.(1)第一束:3x+2y+z (2)( =2x+2y+3z-3x-2y-z =(2x-3x)+(2y-2y)+(3z-z) 技能训练1.((D4.5x^-3x+1;27 6.(1)( =-xy+3y^-x^
(2)-3(2xy-2y^+8x^)+2(9x^+3xy-5y^) =-6xy+6y^-24x^+18x^+6xy-10y^
=(-6xy+6xy)+(6y^-10y^)+(-24x^+18x^) =-4y^-6x^
课程导报网 6